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Class 9 Ganita ManjariClass 9 Maths Solutions | 2026–27
Chapter 2: Introduction to Linear PolynomialsPage 29 – 31All 1 Questions on This Page

Class 9 Maths Chapter 2 Exercise Set 2.6 Solutions

Complete step-by-step solutions for Class 9 Mathematics Ganita Manjari Chapter 2 Exercise Set 2.6 (Question 1, subparts i–v). Covers drawing graphs of sets of linear equations on the coordinate plane, plotting via two convenient points (x = 0 and x = 1), and reflecting on the geometric roles of parameters a (steepness and direction) and b (y-intercept and vertical shift).

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Key Concepts for Exercise Set 2.6

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1

Role of a: Direction and Steepness (Slope)

In the linear equation y = ax + b, the coefficient a controls the inclination of the line. If a > 0, the line rises from left to right; if a < 0, it falls from left to right. A greater magnitude |a| produces a steeper line.

a > 0 (Rising) | a < 0 (Falling) | Larger |a| ⇒ Steeper line
2

Role of b: y-Intercept and Vertical Shift

Setting x = 0 gives y = b, meaning the point (0, b) is the y-intercept. When b = 0, the line passes directly through the origin (0, 0). Varying b while keeping a constant shifts the line vertically without changing its slope.

At x = 0, y = b ⇒ y-intercept is (0, b)
3

Parallel Lines with Equal a

Lines sharing the exact same coefficient a possess identical inclination and slope. If their b values differ, they never intersect and form a set of parallel lines.

Same a, different b ⇒ Parallel lines
4

Opposite Signs of a: Mirror Reflection

Pairing lines with opposite signs of a (such as y = 5x and y = −5x) gives lines with equal steepness (|a|) but opposite directions, forming symmetrical reflections across the coordinate axes.

y = ax and y = −ax ⇒ Equal steepness, opposite directions

Draw the graphs of the following sets of lines. In each case, reflect on the role of 'a' and 'b'. (i) y = 4x, y = 2x, y = x (ii) y = −6x, y = −3x, y = −x (iii) y = 5x, y = −5x (iv) y = 3x − 1, y = 3x, y = 3x + 1 (v) y = −2x − 3, y = −2x, y = 2x + 3

Solution

A straight line is completely determined by any two distinct points on it. For each equation, we choose the two convenient values x = 0 and x = 1 to find the coordinates to plot.

(i) y = 4x, y = 2x, y = x

Points to plot (using x = 0 and x = 1):

Equation When x = 0 When x = 1
y = 4x (0, 0) (1, 4)
y = 2x (0, 0) (1, 2)
y = x (0, 0) (1, 1)

Reflection on a and b:

All three equations have b = 0, so all three lines pass through the origin (0, 0).

The values of a are 4, 2, and 1. All are positive, so all three lines rise from left to right.

As the value of a increases, the line tilts more sharply upwards and becomes steeper.

Hence, a determines the steepness of the line.
(ii) y = −6x, y = −3x, y = −x

Points to plot (using x = 0 and x = 1):

Equation When x = 0 When x = 1
y = −6x (0, 0) (1, −6)
y = −3x (0, 0) (1, −3)
y = −x (0, 0) (1, −1)

Reflection on a and b:

For all three lines, b = 0, so all pass through the origin (0, 0).

Their a-values are −6, −3, and −1. Since a is negative, all three lines fall from left to right.

Comparing their absolute magnitudes: |−6| > |−3| > |−1|, meaning y = −6x is the steepest and y = −x is the least steep.

Therefore, the sign of a determines the direction, and the magnitude |a| determines the steepness of the line.
(iii) y = 5x, y = −5x

Points to plot (using x = 0 and x = 1):

Equation When x = 0 When x = 1
y = 5x (0, 0) (1, 5)
y = −5x (0, 0) (1, −5)

Reflection on a and b:

Both lines have b = 0, so both pass through the origin (0, 0).

Their a-values are 5 and −5. They have the same absolute magnitude:

|5| = |−5| = 5
Therefore, both lines have identical steepness, but opposite directions (one rising, one falling).

The two lines form symmetric mirror images of each other. Changing the sign of a reverses the direction of the line without changing its steepness.

(iv) y = 3x − 1, y = 3x, y = 3x + 1

Points to plot (using x = 0 and x = 1):

Equation When x = 0 When x = 1
y = 3x − 1 (0, −1) (1, 2)
y = 3x (0, 0) (1, 3)
y = 3x + 1 (0, 1) (1, 4)

Reflection on a and b:

All three equations have the same coefficient a = 3. Therefore, all three lines have identical steepness and slope, making them parallel.

Their b-values are −1, 0, and 1. When x = 0, y = b, so they intersect the y-axis at (0, −1), (0, 0), and (0, 1) respectively.

Hence, changing b while keeping a fixed shifts the line vertically without changing its slope.
(v) y = −2x − 3, y = −2x, y = 2x + 3

Points to plot (using x = 0 and x = 1):

Equation When x = 0 When x = 1
y = −2x − 3 (0, −3) (1, −5)
y = −2x (0, 0) (1, −2)
y = 2x + 3 (0, 3) (1, 5)

Reflection on a and b:

For the first two lines, y = −2x − 3 and y = −2x, the value of a is the same (a = −2). Hence, these two lines have identical slope and are parallel. Their b-values are different (−3 and 0), so their y-intercepts are (0, −3) and (0, 0).

For the third line, y = 2x + 3, the value of a is 2 (positive), so it slopes upward from left to right with y-intercept (0, 3).

Although y = −2x and y = 2x + 3 have the same steepness (|−2| = |2| = 2), their directions are opposite because their signs of a differ.

Thus, a determines both direction and steepness, while b controls the vertical position (y-intercept).
Overall Reflection on the Roles of a and b

For any linear relationship in standard form:

y = ax + b

1. Role of a (Slope / Steepness / Direction):

•If a > 0, the line rises from left to right.
•If a < 0, the line falls from left to right.
•The absolute magnitude |a| determines the steepness: a larger |a| produces a steeper line.
•Lines with the same value of a have the same slope and are parallel (when b differs).
•Reversing the sign of a reverses the line's direction without altering its steepness.

2. Role of b (y-Intercept / Vertical Position):

•When x = 0, y = b. Thus, the line crosses the y-axis at (0, b).
•When b = 0, the line passes directly through the origin (0, 0).
•Changing b shifts the line vertically upwards (if b increases) or downwards (if b decreases) without changing its slope.
Answer:Role of a: Determines steepness and direction (rising if a > 0, falling if a < 0; larger |a| is steeper). | Role of b: Determines y-intercept (0, b) and vertical shift; b = 0 passes through origin (0, 0). Equal a gives parallel lines.

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