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Naman Academy For Class 9
Chapter 14: Math of Space: Surface Area and VolumePage 134All 9 Questions on This Page

Class 9 Maths Chapter 14 Exercise Set 14.3 Solutions

Step-by-step solutions for Class 9 Mathematics Ganita Manjari Part 1I Chapter 14 Exercise Set 14.3 (Questions 1–9, Page 134). Covers curved surface area, total surface area, and volume of right circular cones, finding base radius and slant height, fabric requirement for conical tents with wastage, solid generated by rotating a right-angled triangle, and volume fraction of a conical cup filled to half depth.

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Key Concepts for Exercise Set 14.3

Jump to Question 1
1

Slant Height of a Right Circular Cone

For a right circular cone of base radius r and vertical height h, the slant height l represents the hypotenuse of the right-angled triangle formed by the axis and radius.

l² = h² + r² ⇒ l = √(h² + r²)
2

Curved Surface Area of a Cone

The curved (lateral) surface area of a right circular cone is obtained by unrolling its curved surface into a circular sector of radius l and arc length 2πr.

CSA = πrl
3

Total Surface Area of a Cone

The total surface area (TSA) of a cone includes its curved surface area plus the area of its flat circular base.

TSA = CSA + πr² = πrl + πr² = πr(l + r)
4

Volume of a Right Circular Cone

The volume of a right circular cone is one-third the volume of a cylinder having the same base radius r and height h.

V = (1/3)πr²h
5

Generation of a Cone by Rotating a Right Triangle

When a right triangle is rotated through 360° about one of its perpendicular legs of length h, the other leg forms the circular base radius r, and the hypotenuse forms the slant height l.

Height = h, Radius = r, Slant height = l = √(h² + r²)

Find the total surface area of a cone, if its slant height is 21 m and diameter of its base is 24 m.

Solution
Given:
Slant height, l = 21 m
Diameter of the base = 24 m
Therefore, the radius is

r = 242 = 12 m

The total surface area of a cone is

TSA = πrl + πr² = πr(l + r)

Using π ≈ 3.14,

TSA = 3.14 × 12 × (21 + 12)

= 3.14 × 12 × 33
= 1243.44 m²
Answer:Total surface area = 1243.44 m²

Find the curved surface area of a right circular cone whose slant height is 10 cm and base radius is 7 cm.

Solution
Given:
Slant height, l = 10 cm
Radius, r = 7 cm

The curved surface area of a cone is

CSA = πrl
Using π ≈ 227,
CSA = (227) × 7 × 10
= 22 × 10
= 220 cm²
Answer:Curved surface area = 220 cm²

The height of a cone is 16 cm, and its base radius is 12 cm. Find the curved surface area and the total surface area of the cone.

Solution
Given:
Height, h = 16 cm
Radius, r = 12 cm

First, find the slant height using the relation given in the chapter:

l² = h² + r²
l² = 16² + 12²
= 256 + 144
= 400
l = √400 = 20 cm
Curved surface area
CSA = πrl
Using π ≈ 3.14,
CSA = 3.14 × 12 × 20
= 753.6 cm²
Curved surface area = 753.6 cm²
Total surface area
TSA = πrl + πr²

TSA = 3.14 × 12 × 20 + 3.14 × 12²

= 753.6 + 452.16
= 1205.76 cm²
Answer:Curved surface area = 753.6 cm² | Total surface area = 1205.76 cm²

A cone has a height of 15 cm. If its volume is 1570 cm³, find the radius of the base.

Solution
Given:
Height, h = 15 cm
Volume, V = 1570 cm³

The volume of a cone is

V = (13)πr²h
Using π ≈ 3.14,

1570 = (13) × 3.14 × r² × 15

1570 = 5 × 3.14 × r²
1570 = 15.7r²
r² = 157015.7
r² = 100
r = √100 = 10 cm

Since the radius is positive,

Answer:Radius of the base = 10 cm

The curved surface area of a cone is 308 cm² and its slant height is 14 cm. Find (i) the radius of the base, (ii) the total surface area of the cone.

Solution
Given:
Curved surface area, CSA = 308 cm²
Slant height, l = 14 cm
(i) Find the radius of the base

The curved surface area of a cone is

CSA = πrl
Using π ≈ 227,
308 = (227) × r × 14
308 = 44r
r = 30844
r = 7 cm
Radius of the base = 7 cm
(ii) Find the total surface area of the cone

The total surface area of a cone is

TSA = CSA + πr²
Substituting the given values and r = 7 cm,
TSA = 308 + (227) × 7²
= 308 + 154
= 462 cm²
Answer:Radius of the base = 7 cm | Total surface area = 462 cm²

A joker's cap is in the form of a right circular cone of base radius 7 cm and height 24 cm. Find the area of the sheet required to make 10 such caps.

Solution
Given:
Radius, r = 7 cm
Height, h = 24 cm

First, find the slant height using the relation

l² = h² + r²
l² = 24² + 7²
= 576 + 49
= 625
l = √625 = 25 cm

A joker's cap is open at the bottom, so only its curved surface needs to be covered.

The curved surface area of a cone is

CSA = πrl
Using π ≈ 227,

CSA of one cap = (227) × 7 × 25

= 550 cm²
Therefore, the sheet required for 10 caps is
Total area = 10 × 550
= 5500 cm²
Answer:Area of sheet required = 5500 cm²

What length of tarpaulin 3 m wide is required to make a conical tent of height 8 m and base radius 6 m? Assume that the extra length of material required for stitching margins and wastage in cutting is 20 cm.

Solution
Given:
Height, h = 8 m
Radius, r = 6 m
Width of tarpaulin = 3 m

Extra length required = 20 cm = 0.2 m

First, find the slant height:

l² = h² + r²
l² = 8² + 6²
= 64 + 36
= 100
l = √100 = 10 m

The tent has no floor, so only its curved surface needs to be covered.

CSA = πrl
Using π ≈ 3.14,
Area of tarpaulin = 3.14 × 6 × 10
= 188.4 m²

Since the tarpaulin is 3 m wide,

Length required = AreaWidth
= 188.43
= 62.8 m
Adding 0.2 m for stitching margins and cutting wastage,
Total length = 62.8 + 0.2
= 63 m
Answer:Length of tarpaulin required = 63 m

A right triangle with sides 6 cm, 8 cm and 10 cm is rotated through 360° about the side of 8 cm. Find the volume and the curved surface area of the solid so formed.

Rotating the right triangle about the 8 cm leg generates a right circular cone with height h = 8 cm, base radius r = 6 cm, and slant height l = 10 cm.

Solution

When the triangle is rotated through 360° about the side of 8 cm, it forms a right circular cone.

The dimensions of the cone are:

Height, h = 8 cm
Radius, r = 6 cm
Slant height, l = 10 cm
(i) Volume of the cone

The volume of a cone is

V = (13)πr²h
Using π ≈ 3.14,

V = (13) × 3.14 × 6² × 8

= (13) × 3.14 × 36 × 8
= 301.44 cm³
Volume = 301.44 cm³
(ii) Curved surface area of the cone

The curved surface area of a cone is

CSA = πrl
CSA = 3.14 × 6 × 10
= 188.4 cm²
Answer:Volume = 301.44 cm³ | Curved surface area = 188.4 cm²

Suppose you have a cup in the shape of a right circular cone. Fill it with water to half the depth of the cone. What fraction of the volume of the cup is occupied by the water?

When a conical cup is filled to half depth (h = H/2), the radius of the water surface is also halved (r = R/2), resulting in a water volume that is (1/2)³ = 1/8 of the cup's total volume.

Solution

Let the height and base radius of the cup be H and R, respectively.

The volume of the whole cone is

Vcup = (13)πR²H

The water fills the cup to half its depth. Therefore, the height of the water-filled cone is

h = H / 2

Since the water surface is parallel to the circular top of the cup, the water forms a smaller cone of the same shape. Its height is half the height of the whole cone, so its radius is also half the original radius:

r = R / 2

The volume of the water is

Vwater = (13)πr²h
Substituting r = R/2 and h = H/2,
Vwater = (13)π(R/2)²(H/2)
= (13)π(R²/4)(H/2)
= (124)πR²H
Therefore, the fraction of the cup's volume occupied by water is
Vwater / Vcup = ((124)πR²H) / ((13)πR²H)
= 18
Fraction occupied by water = 18
Thus, filling the conical cup to half its depth means the water occupies only one-eighth of its total volume.
Answer:Fraction occupied by water = 18

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